這篇文章給大家分享的是用PHP如何實(shí)現(xiàn)排課的內(nèi)容，下文介紹了兩種排課方式，小編覺得挺實(shí)用的，因此分享給大家做個(gè)參考，文中示例代碼介紹的非常詳細(xì)，感興趣的朋友接下來(lái)一起跟隨小編看看吧。
固定每周的固定時(shí)間上課（例：共上20節(jié)，每周六、周日早上8點(diǎn)-10點(diǎn)上課。假如今天周六凌晨1點(diǎn)，那么排課也需要從今天開始）總共上幾個(gè)周，每周上課時(shí)間比較個(gè)性化（例：共上三周，第一周周一周二早上8點(diǎn)-10點(diǎn)上課；第二周周三周四下午8點(diǎn)-10點(diǎn)上課；第三周周日中午11點(diǎn)-12點(diǎn)上課。）
第一種排課比較好實(shí)現(xiàn)，簡(jiǎn)要代碼如下：
/**
* 生成日期列表
*
* @param int $startDate 開始日期 時(shí)間戳格式
* @param array $timeList 課時(shí)計(jì)劃列表
[
{
"start_at": "09:09", //開課時(shí)間
"end_at": "10:09", //結(jié)束時(shí)間
"week_at": 1 //周幾
},
{
"start_at": "12:09", //開課時(shí)間
"end_at": "13:09", //結(jié)束時(shí)間
"week_at": 1 //周幾
},
{
"start_at": "09:09",
"end_at": "10:09",
"week_at": 5
}
]
* @param int $amount 課時(shí)計(jì)劃數(shù)量
* @param int $skipHoliday 跳過節(jié)假日
*
* @return array
*/
public function generateDateList($startDate, $timeList, $amount, $skipHoliday = 0)
{
// 計(jì)算開始日期是周幾
$startDateWeek = intval(date('N', $startDate));
//規(guī)范化課時(shí)數(shù)據(jù) week_at 做key的三維數(shù)組
foreach ($timeList as $item) {
$weekAt = $item['week_at'];
array_splice($item, 0, 0, $weekAt);
$key = array_shift($item);
$weeksTime[$key][] = $item;
$item = null;
}
unset($timeList);
if (empty($weeksTime)) {
$this->addError('課時(shí)計(jì)劃數(shù)據(jù)為空');
return false;
}
//設(shè)置跳過假期,獲取開始日期之后的節(jié)假日
if ($skipHoliday) {
$holiday = new Holiday();
$holidayData = $holiday->getHolidayList($startDate);
$holiday = null;
unset($holiday);
}
$nowTime = time();
$list = array();
for ($weekStartTime = $startDate, $count = 0; $count < $amount; $weekStartTime += 86400 * 7) {
//$currentWeek :周幾
foreach ($weeksTime as $currentWeek => $weekTime) {
foreach ($weekTime as $time) {
//算出對(duì)應(yīng)的日期時(shí)間戳
$currentDateTime = $weekStartTime + (($startDateWeek <= $currentWeek ?
($currentWeek - $startDateWeek) : (7 - $startDateWeek + $currentWeek)) * 86400); //對(duì)應(yīng)的日期 = 開始時(shí)間 + ((開始時(shí)間對(duì)應(yīng)周 <= 數(shù)據(jù)對(duì)應(yīng)的周幾 ？ (數(shù)據(jù)對(duì)應(yīng)的周幾 - 開始時(shí)間對(duì)應(yīng)周) ：
//（7 - 開始時(shí)間對(duì)應(yīng)周 + 數(shù)據(jù)對(duì)應(yīng)的周幾）) * 86400)
//假期跳過排課
if ($skipHoliday && !empty($holidayData)) {
$startUnix = $currentDateTime + $time['start_at'] * 3600; //開始時(shí)間
$endUnix = $currentDateTime + $time['end_at'] * 3600; //結(jié)束時(shí)間
$skip = false;
//選擇跳過節(jié)假日，且節(jié)假日與當(dāng)前課程時(shí)間有重疊跳過
foreach ($holidayData as $item) {
if (($item['start_at'] < $endUnix && $item['end_at'] > $startUnix) || ($item['start_at'] ===
$startUnix && $item['end_at'] === $endUnix)) {
$skip = true;
continue;
}
}
if ($skip) {
continue;
}
}
$currentDate = date('Y/m/d', $currentDateTime);
$startAt = strtotime($currentDate . $time['start_at'] . ':00');
$endAt = strtotime($currentDate . $time['end_at'] . ':00');
if($startAt < $nowTime || $endAt < $nowTime){
$this->addError('上課時(shí)間不能小于當(dāng)前時(shí)間');
return false;
}
$list[] = [
'date_at' => $currentDateTime, //日期
'week_at' => $currentWeek, //周幾
'start_at' => $startAt,
'end_at' => $endAt
];
$count++;
if ($count >= $amount) {
break 3;
}
}
}
}
$weeksTime = null;
unset($weeksTime);
return $list;
}
（例子，只用來(lái)展示數(shù)據(jù)結(jié)構(gòu)）假如總共5節(jié)課時(shí)，從6-25日開始排課，每周一、周六上課：
（例子，只用來(lái)展示數(shù)據(jù)結(jié)構(gòu)）排課結(jié)果為：
第二種排課方式稍微麻煩一點(diǎn)，簡(jiǎn)要代碼如下：
/**
* 生成日期列表
*
* @param int $startDate 開始日期 時(shí)間戳格式
* @param array $taskList 任務(wù)列表
[
{
"start_at": "09:09", //開始上課時(shí)間
"end_at": "10:09", //結(jié)束時(shí)間
"week_at": 1, //周幾
"week_number": 1 //第幾周
},
{
"start_at": "09:09",
"end_at": "10:09",
"week_at": 2,
"week_number": 1
},
{
"start_at": "09:09",
"end_at": "10:09",
"week_at": 1,
"week_number": 3
}
]
*
* @return array
*/
public function generateDateList($startDate, $taskList)
{
// 計(jì)算開始日期是周幾
$startDateWeek = intval(date('N', $startDate));
$list = [];
$nowTime = time();
$weekSign = $week = 0;
foreach($taskList as $key => $task){
if($task['week_number'] > $weekSign && $task['week_number'] != $week){
$weekSign = $task['week_number'] - $week;
}
//計(jì)算每條數(shù)據(jù)對(duì)應(yīng)的日期 $key == 0：確定第一周第一節(jié)課是在本周還是下一周
if($key == 0 || $task['week_number'] == $week){
if($task['week'] >= $startDateWeek){
$task['date_at'] = $startDate +
(($weekSign - 1) * 7 + ($task['week'] - $startDateWeek)) * 86400;
}else{
$task['date_at'] = $startDate +
(($weekSign) * 7 - ($startDateWeek - $task['week'])) * 86400;
}
}else{
if($task['week'] > $startDateWeek){
$task['date_at'] = $startDate +
(($weekSign) * 7 + ($task['week'] - $startDateWeek)) * 86400;
}else{
$task['date_at'] = $startDate +
(($weekSign) * 7 - ($startDateWeek - $task['week'])) * 86400;
}
}
$startDateWeek = intval(date('N', $task['date_at']));
$week = $task['week_number'];
$startDate = $task['date_at'];
$dateAt = date('Y/m/d', $task['date_at']);
$startAt = strtotime($dateAt . '00:00:00');
if($task['start_at']){
$startAt = strtotime($dateAt . $task['start_at'] . ':00');
}
$endAt = strtotime($dateAt . '23:59:59');
if($task['end_at']){
$endAt = strtotime($dateAt . $task['end_at'] . ':00');
}
if($startAt < $nowTime || $endAt < $nowTime){
$this->addError('上課時(shí)間不能小于當(dāng)前時(shí)間');
return false;
}
$task['start_at'] = $startAt;
$task['end_at'] = $endAt;
//生成課時(shí)數(shù)據(jù)
$list[] = [
'date_at' => $task['date_at'],
'week_at' => $task['week'],
'start_at' => $startAt,
'end_at' => $endAt
];
}
return $list;
}
（例子，只用來(lái)展示數(shù)據(jù)結(jié)構(gòu)）排課數(shù)據(jù)：
（例子，只用來(lái)展示數(shù)據(jù)結(jié)構(gòu)） 排課結(jié)果：
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